0=-2x^2-8x+18

Solution for 0=-2x^2-8x+18 equation:

0=-2x^2-8x+18

We move all terms to the left:

0-(-2x^2-8x+18)=0

We add all the numbers together, and all the variables

-(-2x^2-8x+18)=0

We get rid of parentheses

2x^2+8x-18=0

a = 2; b = 8; c = -18;
Δ = b2-4ac
Δ = 82-4·2·(-18)
Δ = 208
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{208}=\sqrt{16*13}=\sqrt{16}*\sqrt{13}=4\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{13}}{2*2}=\frac{-8-4\sqrt{13}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{13}}{2*2}=\frac{-8+4\sqrt{13}}{4}
$